Calculating Resonant Frequency of a Bridge with Added Support

  • Thread starter Thread starter Haftred
  • Start date Start date
  • Tags Tags
    Bridge Waves
AI Thread Summary
To calculate the new resonant frequency of a bridge with an added support, start by understanding that the natural frequency of the original bridge is 10 Hz. The placement of the support at one-third of the bridge's length alters the harmonic distribution, requiring a new wavelength calculation. The new wavelength with the support is determined to be (2/3)L, where L is the original length of the bridge. By using the relationship between frequency, wavelength, and the speed of waves, the new frequency can be derived and compared to the original 10 Hz. This approach highlights the impact of structural changes on resonant frequencies.
Haftred
Messages
53
Reaction score
0
I am having trouble with the following question:

A bridge has a natural frequence of 10 Hz. If a support is placed one-third of the way along the bridge, what is the new resonant frequency?

How should I start this problem?
 
Physics news on Phys.org
When you place a bridge somewhere between the ends, you alter the way the harmonics are distributed.
 
Take "L" to be the length of the original bridge. A wave MUST have a node at the two endpoints where the bridge is fixed so knowing the frequency, you can calculate the wavelength(s) of the resonant frequency in terms of L. If a support is placed at at 1/3 L a resonant frequency must have wave length 2(1/3)L= (2/3)L (2 because there is a node in the middle of a wave length). Calculate the frequency from that (again in terms of L) and compare with the original value.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top