Calculating temperature with energy absorbed

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Two pitchers of lemonade, one made of copper and the other of glass, each weighing 965 g, absorb 1,000 J of energy in 10 minutes. Over one hour, they absorb a total of 6,000 J. The temperature increase for copper is calculated to be 16°C, while for glass it is 7.4°C, using the formula Q=mcΔT. The specific heat capacities for copper and glass are 3.8 x 10^2 J/(kg°C) and 8.4 x 10^2 J/(kg°C), respectively. The discussion concludes with a successful calculation of temperature changes for both materials.
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Homework Statement



Two pitchers of lemonade are left sitting in the sun at a picnic. One pitcher is made of copper and the other of glass. If each empty pitcher has a mass of 965 g and absorbs 1.0 x 10^3 J of energy 10.0 minutes, calculate the temperature increase of both empty pitchers in 1.0 hours.

Homework Equations



Q=mcΔT

The Attempt at a Solution



I still have no idea.
I tried rearranging the equations... and turning it into seconds...
My book says the answer for copper is 16°C and glass is 7.4°C.

Homework Statement


 
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If the pitchers absorb 1000J of energy in 10 minutes, how much energy will they absorb in 1 hour?
 
Xisune said:
If the pitchers absorb 1000J of energy in 10 minutes, how much energy will they absorb in 1 hour?

1000J in 10 minutes
60/10 = 6
∴ 6 x 1000 = 6000J in one hour?
 
Yes, now use that value for Q.
 
Xisune said:
Yes, now use that value for Q.

but isn't Q already 6000J/h? i am looking for temperature which is T.. so should i rearrange fore T= Q/mc ?

Q= heat or energy absorbed (J) = 6000J/h
m= mass (kg) = 0.965kg
c= specific heat capacity(J/(kg°C) ) = for copper: 3.8 x 10^2 and for glass: 8.4 x 10^2


right?
 
YAY! from that, I got it. Thank you! :)
 

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