- #1
itryphysics
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concave mirror!
The real image produced by a concave mirror is found to be 0.756 times the size of the object. If the distance from the mirror to the screen on which the image appears is 0.764 m , what is the focal length of the mirror?
(a) 1 /do + 1/di = 1/f
(b) image height / object height=m = - di/do
(c) - object height / image height = do / di
m= 0.756 = -hi / ho
so to use equation "c"
i inverted --- > -1/0.756
then set it euqal to rest of the equation so --> -1/.756 = do / .764
do= -1.01058 m
then i used equation "a"
(1/-1.01058) + (1/.764) = 1/f and solved for f
Answer was Wrong. Please tell me what I need to do. Thank you!
Homework Statement
The real image produced by a concave mirror is found to be 0.756 times the size of the object. If the distance from the mirror to the screen on which the image appears is 0.764 m , what is the focal length of the mirror?
Homework Equations
(a) 1 /do + 1/di = 1/f
(b) image height / object height=m = - di/do
(c) - object height / image height = do / di
The Attempt at a Solution
m= 0.756 = -hi / ho
so to use equation "c"
i inverted --- > -1/0.756
then set it euqal to rest of the equation so --> -1/.756 = do / .764
do= -1.01058 m
then i used equation "a"
(1/-1.01058) + (1/.764) = 1/f and solved for f
Answer was Wrong. Please tell me what I need to do. Thank you!
