Calculating the Height of Earth's Atmosphere with Physics Math | Expert Help

  • Thread starter Thread starter EdenKhan
  • Start date Start date
  • Tags Tags
    Physics
AI Thread Summary
To calculate the height of Earth's atmosphere above a 1 square meter surface, the pressure is given as 100,000 Newtons per square meter (100 kPa) and the density as 1.2 kg/m³. Using the formula P = ρgh, where P is pressure, ρ is density, g is the acceleration due to gravity (approximately 9.8 m/s²), and h is height, the problem can be solved. By rearranging the formula to h = P / (ρg) and substituting the known values, the height is calculated to be approximately 8,503 meters. This method emphasizes the importance of unit conversion and applying the correct physics formulas for problem-solving.
EdenKhan
Messages
1
Reaction score
0
Im pretty bad at these physics math problems and our book doesn't go over how to do them very much so I was wondering if I could get some help..

The problem is The weight of the atmosphere above 1 square meter of the Earth's surface is 100 000 Newtons. If the density of the atmosphere were a constant 1.2 kg/m(cubed), calculate where the top of the atmosphere would be.

Okay so we have the weight of the atmosphere as 100,000 Newtons, the density is 1.2 kg/m(cubed). We learned that the pressure of the atmosphere is 100,000 Newtons per meter squared, or 100 kilo pascals.

There a special formula in our to calculate how high the atmosphere is based on the density or the pressure?

thanks very much
 
Physics news on Phys.org
basically what you would want to do there, since you already know two of the dimensions of the volume(length=1m and width=1m), is figure out what the 100,000N is in kg and divide that by how many kilos it is per m^3. because you have a 1x1 square, the number of cubic meters will also be the height, because 1x1xY=Y
 


To solve this problem, we can use the formula P = ρgh, where P is pressure, ρ is density, g is the acceleration due to gravity, and h is the height. We know the pressure (100 kPa) and density (1.2 kg/m^3), so we can rearrange the formula to solve for h.

First, we need to convert the pressure from kilo pascals to pascals, which is the standard unit for pressure. This can be done by multiplying 100 kPa by 1000, giving us 100,000 pascals.

Next, we can plug in the values into the formula:

100,000 pascals = (1.2 kg/m^3) * g * h

We can rearrange the formula to solve for h:

h = 100,000 pascals / (1.2 kg/m^3 * g)

Now we need to determine the value of g. This is the acceleration due to gravity, which is approximately 9.8 m/s^2.

Plugging in the value for g, we get:

h = 100,000 pascals / (1.2 kg/m^3 * 9.8 m/s^2)

Simplifying, we get:

h = 100,000 pascals / 11.76 kg/m^3

Finally, we can solve for h by dividing 100,000 pascals by 11.76 kg/m^3, giving us a height of approximately 8,503 meters. This is the height of the atmosphere above 1 square meter of the Earth's surface.

I hope this helps with your problem-solving and understanding of physics math. Remember to always check your units and use the correct formula for the given problem. Good luck!
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top