Calculating the Speed of a Dropped Rock on Mars

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To calculate the speed of a rock dropped from a height of 0.90 m on Mars, the relevant equation is Vf^2 = Vo^2 + 2ad, where Vf is the final speed, Vo is the initial speed (0 in this case), a is the acceleration (3.73 m/s²), and d is the distance (0.90 m). The initial attempt used incorrect calculations, leading to confusion about the correct method. Including units in calculations is emphasized for clarity. The correct final speed can be determined using the appropriate equation, ensuring accurate results.
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Homework Statement



An astronaut on Mars drops a rock straight downward from a height of 0.90 m. If the acceleration of gravity on Mars is 3.73 m/s2, what is the speed of the rock when it lands?
find m/s

The Attempt at a Solution



.90m/3.73m/s2=.2413
squareroot .2413=.491

.90m+1/2(3.73m/s2)(.491)
=1.816m/s
it was wrong what equation am i suppose to use?
 
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There is an easier equation that you can use : Vf^2 = Vo^2 + 2ad.

Also, just a suggestion, it's a lot easier to help you when you put units on your answers.
 
ill remember that
 
I got the right answer I think I am just having a hard time with what equations I have to use.
 
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