Calculating the voltage and electric field strength between two parallel plates

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SUMMARY

The voltage U between two evenly electrified parallel plates, separated by a distance d of 1 cm with an electric field strength E of 1 V/m, is calculated to be 0.01 V using the formula V = E * d. The force on the surface unit between the plates is determined to be 200 N when the charge Q is calculated as 200 C. Doubling the distance to 2 cm results in a new voltage of 0.02 V and a force of 100 N. The relationship between electric field strength and force is maintained when voltage is constant, requiring further exploration of the equations provided.

PREREQUISITES
  • Understanding of electric field strength and voltage relationships (V = E * d)
  • Familiarity with Coulomb's law and force calculations (F = Q * E)
  • Knowledge of capacitance and charge relationships (Q = CV)
  • Basic grasp of permittivity constant (ε(0) = 8.85 × 10^-12 As / Vm)
NEXT STEPS
  • Explore the implications of maintaining constant voltage while altering plate distance.
  • Research the concept of capacitance and its relation to parallel plate configurations.
  • Learn about the behavior of electric fields in different configurations, including edge effects.
  • Investigate the effects of dielectric materials on electric field strength and capacitance.
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone involved in electrical engineering or related fields seeking to deepen their understanding of electric fields and forces between charged plates.

mmoadi
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Homework Statement



- How much is the electrical voltage U between two evenly electrified parallel flat plates, distanced d = 1 cm, if the strength of electric field between them is E = 1 V / m? - - What is the strength of electric field to the left and to the right of each plate?
- What is the force on the surface (area) unit between the two plates?
- What are the voltage between the plates and the force on the surface unit as a result of doubling the distance between the two plates?
- How is the strength of the electric field and force between the two plates altered (changed), if the voltage is maintained constant?
Influencing constant is ε(0) = 8.85 × 10^-12 As / Vm.

Homework Equations



V= E*d
F= Q*E
V= Qd/ Aε(0)
E= Q/ Aε(0)

The Attempt at a Solution



First part: How much is the electrical voltage U between two evenly electrified parallel flat plates?

V= 1 V/m* 0.01 m= 0.01 V


Are my calculations for the first part correct?

And I really don't know how to approach the rest of the problem. Can someone please help me? Any hints?
 
Last edited:
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mmoadi said:

Homework Statement



- How much is the electrical voltage U between two evenly electrified parallel flat plates, distanced d = 1 cm, if the strength of electric field between them is E = 1 V / m? - - What is the strength of electric field to the left and to the right of each plate?
- What is the force on the surface (area) unit between the two plates?
- What are the voltage between the plates and the force on the surface unit as a result of doubling the distance between the two plates?
- How is the strength of the electric field and force between the two plates altered (changed), if the voltage is maintained constant?
Influencing constant is ε(0) = 8.85 × 10^-12 As / Vm.

Homework Equations



V= E*d
F= Q*E
V= Qd/ Aε(0)
E= Q/ Aε(0)

The Attempt at a Solution



First part: How much is the electrical voltage U between two evenly electrified parallel flat plates?

V= 1 V/m* 0.01 m= 0.01 V


Are my calculations for the first part correct?

And I really don't know how to approach the rest of the problem. Can someone please help me? Any hints?

Yes, V = 0.01V is correct for the first part. The other equation that you will need is Q = CV. That should give you what you need for the rest.
 
Thank you for helping!

Second part: What is the strength of electric field to the left and to the right of each plate?


I need some help with this part. Any hints?

Third part: What is the force on the surface unit between the two plates?

E= ½ Q*V → Q= 2E/ V
Q= 200 C

F= Q*E= 200 N

Fourth part: What are the voltage between the plates and the force on the surface unit as a result of doubling the distance between the two plates?

d= 2 cm= 0.02 m

V= d*E= 0.02 V
Q= 2E/ V= 100 C
F= Q*E= 100 N

ARE MY CALCULATIONS CORRECT?

Fifth part: How is the strength of the electric field and force between the two plates altered (changed), if the voltage is maintained constant?

I need some help with this part. Any hints?

Thank you for helping!
 
Last edited:

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