Calculating Thrust and Lift Forces for a Jet Fighter Taking Off at 27 Degrees

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To calculate the thrust and lift forces for a jet fighter taking off at a 27-degree angle, the plane's weight is 79,300 N, translating to a mass of approximately 8084 kg. The total force acting on the plane, due to its acceleration of 2.62 m/s², is calculated as 21,179 N. The thrust is not simply the total force but a component of it, and the lift force must be determined using trigonometric functions related to the angle of ascent. Calculations suggest that the lift force could be around 89,000 N, but there is some uncertainty in the results, indicating a need for careful consideration of the forces involved. Properly resolving the forces using Newton's laws and trigonometric relationships is crucial for accurate results.
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A jet fighter takes off at an angle of 27.0 degrees w/ the horizontal, accelerating at 2.62 m/s*s. The plane weighs 79,300 N. I need to find the thrust T of the engine on the plane and the lift force L exerted by the air perpendicular to the wings.

Thanks

My reasoning so far...

79,3000 N / g = 8084 kg.

F = ma = 2.62 m/s^2 * 8092 kg -> 21179 N.

So I'm thinking that be the thrust.

As for the lift force L though, I don't know. Could I use sin or cosine?
 
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Anisotropic Galaxy said:
A jet fighter takes off at an angle of 27.0 degrees w/ the horizontal, accelerating at 2.62 m/s*s. The plane weighs 79,300 N. I need to find the thrust T of the engine on the plane and the lift force L exerted by the air perpendicular to the wings.

Thanks

My reasoning so far...

79,3000 N / g = 8084 kg.

This is the mass of the airplane. You'll need it.

Here's a list of all the forces that act upon the plane:
- gravity
- lift of the wings
- thrust of the engines

That's 3 forces (try to find in what direction they are applied ; make a drawing of the forces). Find the total force.

Now, the airplane is not in equilibrium. It is accelerating. So what should you do with the 3 forces ? What equation should you use ? (hint: Newton...)

F = ma = 2.62 m/s^2 * 8092 kg -> 21179 N.

That should be the total force, yes...

So I'm thinking that be the thrust.

As for the lift force L though, I don't know. Could I use sin or cosine?

No, it is not the thrust. It is the total force (of which thrust is only a part)...

Leave you here...
 
Is the thrust simply cos(27.0)*21179 N then?

So...the force of the lift is 89,000 N, right? a_y = 2.62 m/s^2*sin27.0 = (Lift - mg)/m so then by substituting things, Lift = 89,000 N.
 
But someone else got a different answer than me, so I'm probably wrong here...
 
Does


Should i switch the axis around, and then the Force of the thrust = (2.62cos27-gsin27)m and L equal to (2.62sin27+gcos27)m?

sound right...?
 
or.. maybe not?

L = mgcos27 and T = m(a_x) + mgsin27?
 
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