Calculating Tire Pressure: Ideal Gas Law and Temperature Change

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Homework Help Overview

The problem involves calculating the tire pressure of an automobile tire using the ideal gas law, considering changes in volume and temperature. The original conditions include a temperature of 10.0°C and normal atmospheric pressure, with the air compressed to 26.0% of its original volume and heated to 32.0°C.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the ideal gas law and the relationship between pressure, volume, and temperature. There is a focus on ensuring consistent units for pressure and the potential oversight of including initial pressure in calculations.

Discussion Status

Some participants have offered guidance regarding unit consistency and the importance of including atmospheric pressure in calculations. There is an ongoing exploration of the calculations presented, with no clear consensus on the correct approach yet.

Contextual Notes

Participants note the need for clarity on the values used in calculations, particularly the conversion of atmospheric pressure to pascals. There is also an acknowledgment of the original poster's confusion regarding the results obtained.

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Homework Statement


An automobile tire is inflated with air originally at 10.0°C and normal atmospheric pressure. During the process, the air is compressed to 26.0% of its original volume and the temperature is increased to 32.0°C.
What is the tire pressure? Pa




Homework Equations


Pv=nRT P1V1/T1= P2V2/T2


The Attempt at a Solution



i used p1v1/t1=p2v2/t2 and got 4.15 Pa but it was wrong
 
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make sure you have the same units for p1 and p2
 
yes i checked it. i used 1 atm for the original pressure and then changed it to pa
 
Hi zcabral,

It's difficult to follow your calculation without knowing the numbers you put into your calculation.

However, here I think you forgot to include p1 in your calculation. Or did you not convert it? Atmospheric pressure in pascals is about 1.013\times 10^5 (did you use that number?), so the pressure your getting in your first post is tiny.
 

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