Calculating Total Energy from Combined Rotational Motion of Two Spheres

  • Thread starter Thread starter faklif
  • Start date Start date
  • Tags Tags
    Angles Rotation
AI Thread Summary
The discussion revolves around calculating the total energy of a moving sphere rolling on a larger fixed sphere. The key point is that the total energy includes both the angular velocity from the sphere's own rotation and the angular velocity due to its motion around the center of the fixed sphere. Initially, there was confusion about whether the latter should be considered as regular kinetic energy. However, it was clarified that the angular velocity around the fixed sphere contributes to the overall energy calculation. Understanding this combined effect is crucial for accurately determining the total energy of the system.
faklif
Messages
17
Reaction score
0

Homework Statement


I have a sphere on top of another larger fixed sphere. The sphere on top rolls on the fixed one without sliding. The moving sphere is rolling and therefore has an angular velocity, it also moves giving it an angular velocity around the center of the fixed sphere. To calculate the energy from the rotation I need the rotational speed of the moving sphere.

Homework Equations


The Attempt at a Solution


I know that the answer is supposed to come from adding the angular velocity due to the moving sphere spinning and the angular velocity seen from the center of the larger sphere but I can't really see why. My initial thought, which is wrong, was that the total energy would come from the rotation of the moving sphere and the angular velocity around the center of the fixed sphere would only contribute as "regular" kinetic energy.
 
Physics news on Phys.org
faklif said:

The Attempt at a Solution


I know that the answer is supposed to come from adding the angular velocity due to the moving sphere spinning and the angular velocity seen from the center of the larger sphere but I can't really see why. My initial thought, which is wrong, was that the total energy would come from the rotation of the moving sphere and the angular velocity around the center of the fixed sphere would only contribute as "regular" kinetic energy.

Why do you think that is wrong? It seems right to me. The angular velocity around the center of the fixed sphere is the same as motion of the center-of-mass of the moving sphere, which is "regular" (i.e. translational) kinetic energy.
 
Thanks, I don't know what I was thinking. ;)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top