Calculating Total Resistance of a Cube with Six Ohm Edges | Helpful Tips

AI Thread Summary
The total resistance of a cube with each edge having a resistance of six ohms is calculated to be 30 ohms when measured between opposite corners. To visualize the problem, numbering the corners from 1 to 8 and sketching the resistance network can aid in understanding the connections. Using Kirchhoff's law, the current can be tracked as it divides at each node until reaching the desired corner. The voltage drop across each edge is calculated using the formula v = i*r, and the total resistance is found by summing these voltage drops and dividing by the initial current. This method provides a clear approach to determining equivalent resistance in a cube configuration.
alnywk
Messages
13
Reaction score
0
what is the total resistance of the cube if each edge hv six ohm ?
help me please
i don't know how to draw a simple diagram
 
Physics news on Phys.org
Number the corners from 1 to 8. As you construct the resistance network on paper between the nodes (corners) keep track of your progress by scribbling each edge on the cube out as you make the connections on paper.
 
total resistance of a cube each edge having six ohm resistance is 30 ohm(In case of equivalent resistance calculated between opposite corners).
It means 5*R .where R is the resistance of one edge of cube.

To draw the diagram for the above problem , start from one corner with i current and dividing it according to kirchhoffs law on each node. by this way go to the last node (desired corner).

Now calculate voltage drop on each edge( v = i*r). Sum up all voltage drops and divide by initial current i. By this way you can calculate equivalent resistance between desired corners of the cube.

If you still have any problem mail me.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top