Calculating Truck Speed from Frequency Shift

AI Thread Summary
To calculate the truck's speed from the frequency shift, the Doppler effect equations for sound must be applied. The observed frequency changes from 1100 Hz as the truck approaches to 950 Hz as it moves away. The initial attempt yielded a speed of 47 m/s, but the book states it should be 25 m/s. To resolve this discrepancy, two equations are needed, one for each frequency observation, as both represent the observed frequency rather than the source frequency. Using these equations will allow for the determination of both the source frequency and the truck's speed accurately.
confusedinphys
Messages
3
Reaction score
0

Homework Statement



You are standing by the roadside as a truck approaches, and you measure the dominant frequency of the truck noise at 1100 Hz. As the truck passes, the frequency drops to 950 Hz. What is the truck's speed?

Homework Equations




f'= f (vsound)
-------------------
(vsound-velocity of source)

1100 = 950(340)
------
(340-vs)

The Attempt at a Solution



I rearrange for velocity of source and get 47 m/s, but my book says 25 m/s
 
Physics news on Phys.org
f'= f (vsound)
-------------------
(vsound-velocity of source)
Is one relationship - in this case for frequency change of a sound moving toward the listener/receiver for which there is an increase in frequency

So f' = f (vs/(vs-v)) = 1100 Hz,

for the case where the source passes and is traveling away from the listener/receiver

f' = f (vs/(vs+v)) = 950

Take on equation and rearrange for f

one should obtain

1100 = 950 \big(\frac{v_s\,+\,v}{v_s\,-\,v}\big)
 
Here, you have two unknowns. 1100 Hz, and 950 Hz are both frequencies you observe, neither is the actual frequency of the source. That is, they are both values of f', one for when the truck is approaching you, the other for when the truck is moving away from you.

So, as I said, their are two variables you do not know, the source frequency, and the speed of the source.

HINT: Since you have two unknowns here, you are going to need two equations to solve this problem? Using the doppler shift formula you have above, can you set up two equations corresponding to this situation?

EDIT: (Astronuc you beat me to it!)
 
I really have no idea what you mean by two equations here, can someone fill me in?
 
Look back at Astronuc's post.
Can you summarize his suggestion?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top