Calculating Velocity of a 10-gram Bullet

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To calculate the velocity of a 10-gram bullet fired into a 3.0-kilogram block moving at 30 cm/sec, the conservation of momentum equation is used: m1v1 + m2v2 = m1u1 + m2u2. Here, m represents the mass and v the velocity of each object before impact, while u denotes their velocities after impact. The discussion indicates that the user is seeking guidance on applying this equation to solve for the bullet's initial velocity. After receiving the formula, the user feels confident to proceed with the calculations independently. Understanding the conservation of momentum is crucial for solving such physics problems.
Draygon_Phly
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Hi! I would like to know what equation I would use to figure out this question and why?

A 10-gram bullet is fired into a 3.0-kilograme block, given that the block a velocity of 30 cm/sec. With what velocity was the bullet fired?

Thank you for your answer. [?]
 
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The conservation of momentum:
m_1v_1 + m_2v_2 = m_1u_1 + m_1u_2
So that:
m_ - mass of each object
v_ - velocity of each object before impact
u_ - velocity of each object after impact

Do you need more help or can you figure this out yourself now? :smile:
 
thanx I can figure it out from here.:smile:
 

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