Calculating Velocity of a Free-Falling Object

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To calculate the velocity of a free-falling object from a height of 9 meters, the correct approach involves using a kinematic equation that relates initial and final velocity, acceleration, and displacement, rather than simply multiplying height by gravitational acceleration. The initial suggestion of multiplying 9 meters by 9.81 m/s² is incorrect as it does not account for the proper formula needed for this scenario. The correct final velocity upon striking the ground is approximately 13.29 m/s. For accurate calculations, it is essential to use the appropriate kinematic equation that excludes time. Understanding these principles is crucial for solving free-fall problems effectively.
bad at math gu
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Hi was wondering if i could get some help with this question

-An object is allowed to free fall from rest from a height of 9 m. What will be its velocity on striking the ground?

---My solution to this was to simply multiply the 9m by 9.81m/s... which is wrong the solution posted to this question is 13.29m/s... which formula should be used for this question?

Any help would be greatly appreciated thank you
 
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Hello bad at math gu,

Welcome to Physics Forums!

bad at math gu said:
Hi was wondering if i could get some help with this question

-An object is allowed to free fall from rest from a height of 9 m. What will be its velocity on striking the ground?

---My solution to this was to simply multiply the 9m by 9.81m/s... which is wrong the solution posted to this question is 13.29m/s... which formula should be used for this question?

Any help would be greatly appreciated thank you
That would be sort of the right approach if you were to allow an object to fall from rest for 9 seconds, but not 9 meters. (and you forgot to square the seconds in your acceleration units: 9.81 m/s2)

Find one of your kinematics equations for uniform acceleration that has initial and final velocity, acceleration and displacement (but not time). That's the easiest way to solve this problem. :smile:

You can find such an equation here: https://www.physicsforums.com/showthread.php?t=110015
 
HA got it thank you
 
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