Calculation of rate of climb (vertical velocity)

AI Thread Summary
The discussion centers on calculating the rate of climb (RC) for a UAV, where the user encounters issues with their calculations indicating an RC greater than the velocity vector. It is suggested that the UAV may be overpowered, complicating the use of standard formulas for RC, particularly in steep climbs. The Roskam method is referenced, highlighting that certain equations are only valid under specific conditions, particularly regarding flight path angles. The user is advised to utilize different equations for steep climbs and to iteratively solve for velocity and flight path angle. Ultimately, the conversation emphasizes the need for careful analysis of power-to-weight ratios and appropriate aerodynamic equations to resolve the climbing performance issues.
amirshah
Messages
7
Reaction score
0
Hello my friends,

At the moment, I'm doing an estimation and analysis of flight performance for UAV (unmanned aerial vehicle). During climbing flight analysis, I have a problem regarding calculation of rate of climb (vertical velocity), my calculation value of rate of climb seem weird, the vertical velocity (RC) bigger than velocity vector. If my rate of climb is not correct, so I have faced also difficulty to find absolute and service ceiling. I hope someone can help me to solve this problem quickly, I have already calculate it many time but the result still same. I would like to attach xls file (example of analysis table), so I really want a help from all of you here. I don't know what's the problem in my analysis. Please help me ... If all of you don't understand, ask me for explanation.
 

Attachments

Engineering news on Phys.org
Up front I must say that wading through other person's spreadsheet is quite difficult, as spreadsheets are just not reading-worthy. A better presentation would be made using something that can actually show formulas and comments in a readily understandable way, e.g. Matlab, with a sample evaluation for one input vector. Luckily, here you have quite a simple computation, and I needed a brief diversion, so...

The problem is that your aircraft is massively overpowered. In such a scenario, climbing velocity cannot be computed by the (P_{avail} - P_{req}) / W formula -- this is an approximation that holds for limited thrust/power-to-weight designs.

On the other hand, while I don't know much about small IC engines, it seems unlikely to me that a 4 kW engine could weigh so little that the gross takeoff weight of the whole UAV is only 20 kg.

--
Chusslove Illich (Часлав Илић)
 
Thanks my friend for your opinion. Actually, I just want to show the results of calculation using spreadsheet based on roskam method, so my friends in this forum could analyze. Can you explain to me about this statement

(a) climbing velocity (rate of climb) cannot be computed by the formula -- this is an approximation that holds for limited thrust/power-to-weight designs.

(b) it seems unlikely to me that a 4 kW engine could weigh so little that the gross takeoff weight of the whole UAV is only 20 kg.

Do you have any suggestion, what equations are suitable to solve this problem. It just not rate of climb problem, I'm also facing with the problems of service ceiling, absolute ceiling, range and endurance calculation. From my point of view, the engine is the main problem. What information do you need, so it will allow you to solve the problems?
 
caslav.ilic said:
[...] it seems unlikely to me that a 4 kW engine could weigh so little that the gross takeoff weight of the whole UAV is only 20 kg.

Well, after googling a bit, you can forget about this statement of mine. I thought that the engine wouldn't have power-to-weight higher than 1 kW/kg, but apparently there exist ~5 kW engines with >2 kW/kg PtoW.

The question is still whether you need such a powerfull engine. But that's for you (or someone else) to clarify, as I don't know what special requirements a ~20 kg UAV should have.

If you do need such an engine, then...

amirshah said:
[...] based on roskam method [...] an approximation that holds for limited thrust/power-to-weight designs.

I will assume that by "Roskam method" you refer to e.g. eq. 9.12 in Roskam's "Airplane Aerodynamics and Performance". In that case, observe that 9.12 is usable only if the conditions 9.5 are satisfied; most importantly, the flight path angle \gamma should be small (say < 15 deg).

If you then refer to eqs. 9.3 and 9.4 (which preceede assumptions 9.5), in them you neglect thrust-to-body axis angle \phi_{T} and acceleration dV/dt, rearrange them so that weight term is on the left and everything else on the right, and finally divide 9.3 by 9.4, you end up with:
<br /> \tan \gamma = \frac{T \cos\alpha - D}{T \sin\alpha + L}<br />
or when multiplied by velocity to have it in power-formulation:
<br /> \tan \gamma = \frac{P_{av} \cos\alpha - P_{reqd}}{P_{av} \sin\alpha + LV}<br />
From this you can see that when P_{av} &gt;&gt; P_{reqd} and even (P_{av} \approx LV (as in your case), the angle \gamma will not be small. Thus, 9.5 is no longer applicable.

Do you have any suggestion, what equations are suitable to solve this problem. [...] What information do you need, so it will allow you to solve the problems?

No special equations are needed, the 9.3 and 9.4 and the usual aerodynamic force expressions (X = 0.5 \rho V^2 C_X A) will suffice.

What is needed is adept handling of those expressions. For example, for a given AoA \alpha, the remaining unknowns in 9.3 and 9.4 are the velocity V and the flight path angle \gamma; but, the equations are non-linear, and have to be solved iteratively for these quantities. You could assume \gamma_1 \approx 0 and compute V_1, then use V_1 to compute \gamma_2, then use \gamma_2 to compute V_2, etc. until at one point \gamma_k and V_k pretty much stop changing. Then your climbing velocity for the given AoA will be simply the final V_k \sin\gamma_k.
 
I would like to say thank you for your help. I really confused about

[that the engine wouldn't have power-to-weight higher than 1 kW/kg, but apparently there exist ~5 kW engines with >2 kW/kg PtoW]

Yes, I'm refer to eq. 9.12 in Roskam's "Airplane Aerodynamics and Performance". I have re-read Roskam's book and observe that your ideas and comments are true. Equation 9.12 is good only if the conditions 9.5 are satisfied, the more steepest the climb is the worst this approximation will be, so if our UAV has a big specific excess power, it will climb quite steepy and the results can be not so good to use that equation. The climbing analysis at steep angles I need to use eqns. (9.59), (9.61), (9.62) and (9.64) to solve the problem. I will try these steps.

From your comments, I beginning to think that the main problem is the engine has massive power compare to weight.
 
amirshah said:
I really confused about [...]

Pay no attention. I merely thought that the given engine would be too heavy to put in a UAV of the given size, but then took a better look and found out this is not the case.

The climbing analysis at steep angles I need to use eqns. (9.59), (9.61), (9.62) and (9.64) to solve the problem. I will try these steps.

Yes, these ought to work too. The difference to the procedure I stated above is that you fix the velocity instead of the angle of attack, and then iterate to find the flight path angle. This means that once you have it, you should also check whether the implied angle of attack is admissible (you compute it inversely from the lift curve).

--
Chusslove Illich (Часлав Илић)
 
Posted June 2024 - 15 years after starting this class. I have learned a whole lot. To get to the short course on making your stock car, late model, hobby stock E-mod handle, look at the index below. Read all posts on Roll Center, Jacking effect and Why does car drive straight to the wall when I gas it? Also read You really have two race cars. This will cover 90% of problems you have. Simply put, the car pushes going in and is loose coming out. You do not have enuff downforce on the right...
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly
Back
Top