- #1
icystrike
- 445
- 1
Answer stated is D
Answer stated is DMy attempt at the solution:
For the first question,
the calculations are as follow:
A. P=I2R = 42×12 = 192 J/s -- Missing information
B. Energy = 1/2 mv2 = 15×9= 135J
C. Energy = mgh = 10×10×1 = 100J
D. Work done = 0J ; moving against zero friction.
My answer will therefore B for the first question.
For the second question,
Work done = Ffric × d = 70N×4m = 280J
The information with regards to the mass of the object is irrelevant since the friction coefficient is not stated and the frictional force has been stated in the problem.
My answer is A for the second question.