Calculus: Derivatives Problem #2

Hothot330
Messages
11
Reaction score
0
[SOLVED] Calculus: Derivatives Problem #2

Homework Statement


The graph of y=2x^3+24x-18 is


Homework Equations


y '=6x^2+24
y ''=12x

The Attempt at a Solution


The answer to this is "increasing for all values of x"
But I want to know why...if substituting -1 for x will make the problem a negative.
 
Physics news on Phys.org
What's the question? If you want to find where y is increasing it's where is y' positive. You don't think y' is positive for all x?
 
because when you plug in -1 for y=2x^3+24x-18 the end result is a negative not positive.

The other choices to the questions are:
b.decreasing for all values of x
c.only increasing for values of x on the interval (-infinity,-2)U(2,+infinity)
d.only increasing for values of x on the interval (-2,2)
e. only decrasing for values of x on the interval (-infinity,-2)
 
NVM, TOTAL IDIOT HERE... I know what you're saying now. Thanks.
 
The question isn't where y is negative, it's where y in increasing. y can be increasing even if it's negative.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top