1. The problem statement, all variables and given/known data A 0.080kg copper container (specific heat: 387Jkg-1K-1) contains 0.30kg of water and 0.040kg of ice at 0°C. Steam at 100°C is passed into the water and its temperature stabilizes at 20.0°C. Find the mass of the water left in the container assuming the system is insulated. 2. Relevant equations Q= mcΔT Q= mL 3. The attempt at a solution Q lost = Q gained msteamcΔT + msteamL = mCucΔT + mH20cΔT + micecΔT + miceL msteam = mCucΔT + mH20cΔT + micecΔT + miceL / cΔTsteam + Lsteam Total mass water= mass steam + water + ice Is this correct? Is ΔT for steam -80 (20-100°C)?