Can i get some one to do this probfor me

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To find the volume of the solid formed with a base bounded by y = (x^2)-2 and y=4, the side length of the squares perpendicular to the x-axis is determined to be s = 4 - (x^2 - 2). The volume of a slice of the solid is expressed as dV = s^2dx. The limits for x are found where the two boundary lines intersect, which occurs at the points where (x^2 - 2) equals 4. Integration of the volume slices between these limits will yield the total volume of the solid.
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Find the volume of the solid formed with a base bounded by y = (x^2)-2 and y=4 filled with squares that are perpendicualr to the x-axis.
 
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If your speaking of volume, what are the limits on the z-axis
 
bigskilly said:
Find the volume of the solid formed with a base bounded by y = (x^2)-2 and y=4 filled with squares that are perpendicualr to the x-axis.

One side of each square lies in the x-y plane. The length of a side is s = 4 - [(x^2)-2]. The volume of a slice of the solid is dV = s^2dx. Figure out the limits for x (where the two boundry lines cross, and integrate.
 
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