Can someone explain the confusion with these basic motion equations?

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The discussion revolves around confusion regarding basic two-dimensional motion equations, particularly the compatibility of given values with the formulas. The user encounters an issue when calculating the final velocity using the equation v^2 = vi^2 + 2ax, resulting in a non-real answer due to physically impossible values. It is clarified that the initial displacement value ΔX = 49 was incorrectly rounded and should be ΔX = 48.6 for realistic calculations. Additionally, the second formula for time can be rearranged into a quadratic equation, allowing for solutions through factoring or the quadratic formula. The conversation emphasizes the importance of using physically plausible values in motion equations.
FlamingAero
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I have been reviewing the basic two-dimensional motion equations and I've discovered a conundrum that is causing me much confusion. For example, here is a basic formula with variables:

v^2 = vi^2 + 2ax

v = ?

vi = 27

a = -7.5

x = 49

Therefore:

v^2 = 27^2 + 2(-7.5)(49)

v^2 = 729 + -735

v = √(-6)

When I input the square root of (-6) into my calculator (a TI-83+), I receive a ERR:NONREAL ANS message. Are these values not compatible with this formula?

Here's another similar example, this time with the formula:

ΔX = vi*t + (1/2)at^2

ΔX = 49

vi = 27

a = -7.5

t = ?

I have no idea how to even arrange the equation in terms of t. Is this formula limited to solving displacement?

Thank you for your help and guidance.
 
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FlamingAero said:
Are these values not compatible with this formula?
Your values are just physically impossible. Given that initial velocity and acceleration, you'll never achieve x = 49. (Figure out the maximum value of x.)

Similar issue with the other formula for time. (In general, you can surely solve for the time. You'll get a quadratic equation.)
 
Doc Al said:
Your values are just physically impossible.

I now see my error. The value ΔX = 49 was rounded for significant figures, and should have instead been ΔX = 48.6

Thank you for your help.
 
Last edited:
Yeah the second one is a quadratic so you can either set it to 0 and factorise to get your two answers or use the quadratic formula below

<br /> <br /> \frac{-b\pm\sqrt{b^2-4ac}}{2a}<br />
 
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