Can the Dot Product Determine Maximum Distance from the Origin?

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The discussion revolves around using the dot product of a vector A with itself to determine the maximum distance from the origin. It is established that the square of the distance can be represented as distance² = A·A, and for maximum distance, the derivative A'·A must equal zero, indicating that the velocity vector A' is perpendicular to the position vector A. This condition signifies a turning point in the distance function, confirming that the distance is at a maximum. Participants express confusion about the relationship between perpendicular vectors and maximum distance, but it is clarified that the zero derivative condition indicates a turning point. Overall, the method discussed is validated as a correct approach to finding maximum distance.
jimmy42
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Hello,

If I have a vector A and then I do the dot product on itself so A°A. Then can I use that to find the maximum distance from the origin? If I take the derivative of the dot product then can I know at what time the maximum distance was travelled?

I have done this but it is wrong based on the graph I made using Wolfram Alpha, I just need some reassurance that I'm on the right track.
 
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hello jimmy42! :smile:

your method looks ok …

distance2 = A.A,

so if the distance is a maximum, then A'.A = 0

ie A' is perpendicular to A
 
Why if A'.A =0 is the distance a maximum?

I too have a question on this, and I'm failing to see why if the position vector and the velocity vector are perpendicular then the distance is a maximum if the above holds true.

Cheers in advance

Smithy
 
Welcome to PF!

Hi Smithy! Welcome to PF! :smile:
smith873 said:
Why if A'.A =0 is the distance a maximum?

Because that's the derivative of the distance squared (divided by 2),

so it must be 0 if the distance squared is at a turning-point (maximum minimum or inflection point). :wink:
 
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