Capacitor Circuit: Is My Method Correct? 1. The problem statement, all variables and given/known data Four capacitors, a battery and a switch are assembled in the circuit below. Initially, the switch is set to position A and C4 is uncharged. At t = 0, the switch is moved to B. Find Q4, the charge on C4 when the switch is on B. http://online.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?courses/phys212/oldexams/exam1/fa09/fig20.gif [Broken] 2. Relevant equations Q= CV 3. The attempt at a solution The initial charge on the C3 capacitor = C3 * V1 Now as the switch to moves to B. The total charges remains the same, but the voltage changes. Then Q = ( C3 + C4 ) V2 V2 = Q / ( C3 + C4 ) next with V2 found Q4 = C4 V2 ***************** Ok, so that is the only way i've been able to figure this out, however, arent the capacitors in series? In that case I would have to change the equivalent capacitance equation to 1/(1/C3+1/C4) which doesn't work out. Can someone please explain whats going on? Help would be greatly appreciated. Thanks in advance!