An inductive load is connected to a 120V (rms), 60Hz AC source. The load draws 5.0 kW at a power factor of 0.81 (lagging). You need to improve your power factor to 0.96 (lagging) by adding a capacitor.
What is the Capacitance needed (in uF)?
P/|S| = cos(phi)
Q = V^2/X
S = sqrt(P^2 + Q^2)
The Attempt at a Solution
Please see photo with my solution attached. My professor says the answer is actually 398.17uF. I did this problem multiple times and never got that answer. I keep getting what I got in the photo attached (271uF).
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