Cartesian Coordinates and Cross Product of Vectors for Magnetic Field Direction?

AI Thread Summary
The discussion revolves around the application of Cartesian coordinates and the cross product of vectors to determine the direction of the magnetic field. It clarifies that in the right-hand rule, the positive z direction points out of the page, represented by the equation ##\hat {k} = \hat {\bf \imath } \times\hat {\bf \jmath}##. The corkscrew rule is mentioned to explain the direction of the cross product, indicating that the magnetic field direction can vary based on the position of the charge relative to the wires. Participants express confusion about the problem's clarity, particularly regarding the influence of the charge's proximity to different wires on the magnetic field direction. Overall, the conversation highlights the complexities in understanding vector directions in magnetic field calculations.
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Homework Statement


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Homework Equations

The Attempt at a Solution


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the answer given is the same but without the negative sign, I don't understand because the crossproduct of unit vectors
upload_2017-2-10_15-13-41.png

when using a Cartesian coordinates of the directions given by the right-hand rule? Is the positive z direction pointing out of the page if X and Y are as follows
upload_2017-2-10_15-18-3.png

apologies if this is in the wrong section, thanks for any help in advance
 
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Yes. ##\hat {k} = \hat {\bf \imath } \times\hat {\bf \jmath}## , so z points towards you, out of the screen.

Corkscrew rule I call it. Turn ##\hat{\bf \imath }## over the smallest angle towards ##\hat {k}##. Corkscrew will go in the minus y direction : $$\hat \imath \times\hat k = -\hat \jmath $$
 
The problem doesn't specify which of the two wires the charge -q is a distance b from. Does the answer change if you pick the other wire to be a distance b from -q?
 
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Thank you both your answers, TSny I thought the same, closer to the top wire the combined magnetic field would be in the opposite direction . Maybe the question is just not very good
 
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