A man runs at a speed of 4.0 m/s to catch a standing bus. When his distance to the door is 6.0m, the bus starts moving forward and continues with a constant acceleration of 1.2 m/s2.
a) How many seconds does it take for the man to reach the door ?
b) If at the beginning he is 10.0 m from the door, will he (running at the same speed) ever catch up? Simple answer is not enough - explanatory answer using calculations or graphical method is needed
The Attempt at a Solution
xm= 4*t + 6
t1= -1.26s (rejected because it's <0)
t1= 7.92s (accepted because it's >0)