Center of Mass of system of particles

[BEEFCOPTER]

Homework Statement

Four particles are in a 2-D plane with masses, x- and y- positions, and x- and y- velocities as given in the table below:

M X Y Vx Vy

1 8.9kg -2.6m -4.8m 3.2m/s -3.9m/s

2 7.9kg -3.4m 3.6m -5m/s -5.2m/s

3 9kg 4.7m -5.4m -6.3m/s 2m/s

4 8kg 5.5m 2.7m 4.1m/s - 3.3m/s
OK, so it first asks:
What is the x position of the center of mass
and
What is the y position of the center of massI have answered these correctly as:
CMx =1.07
CMy =-1.22The next question asks:
What is the speed of the center of mass:?

I THOUGHT this would simply be sqrt[(CMx^2) + (CMy^2)] <-(the magnitude of CMy) which would be 1.622 m/s
but this is INCORRECT. I have stared and re-read this question for an hour and simply cannot think of any other way to calculate.

any thoughts would be greatly appreciated?

 

[BEEFCOPTER]

after typing out the question, I may ahve already seen my error, I just calculated the magnitude of the distance from the origin, not its actual speed.. funny how asking the question makes you see things