Chain rule for second derivatives

ehrenfest
Messages
2,001
Reaction score
1

Homework Statement


I cannot believe I do not know this!

dx/dt = dx/dt' dt'/dt is the chain rule for first derivatives

d^2x/dt^2 = ? is the chain rule for second derivatives

if it is complicated could you link me to a source that explains it please

Homework Equations


The Attempt at a Solution

 
Physics news on Phys.org
What's the problem with differentiating the first derivative?
 
d^2x/dt^2 = d^2x/(dt'dt) dt'/dt + dx/dt d^2t'/dt^2?

The product rule was used. That mixed partial seems out of place. Is the above correct?
 
What makes you think there is a "chain rule for second derivatives"?
 
HallsofIvy said:
What makes you think there is a "chain rule for second derivatives"?

Well, is there something wrong with what I posted? Maybe I just discovered it.
 
ehrenfest said:
d^2x/dt^2 = d^2x/(dt'dt) dt'/dt + dx/dt d^2t'/dt^2?

The product rule was used. That mixed partial seems out of place. Is the above correct?
Looks right. If you don't want the mixed partial, then why not apply the chain rule? After all, dx/dt' is merely a function... (Call it y, if you're having trouble thinking about it)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Replies
4
Views
971
Replies
3
Views
2K
Replies
6
Views
1K
Replies
3
Views
2K
Replies
3
Views
1K
Replies
3
Views
1K
Replies
10
Views
2K
Back
Top