Change of internal energy of an ideal gas

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Homework Help Overview

The discussion revolves around the change of internal energy of an ideal gas, specifically focusing on the integration of a given equation involving temperature-dependent terms.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to integrate the provided equation for internal energy but questions the correct form of the integral, particularly regarding the treatment of the first term.

Discussion Status

Participants are actively clarifying the integration process, with some confirming the original poster's understanding of constants in the integral. Guidance has been offered regarding the correct interpretation of the terms in the equation.

Contextual Notes

There is an indication that the original poster is working with specific values to reach a numerical answer, but the exact values and context are not detailed in the discussion.

DevonZA
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Homework Statement


upload_2017-5-16_9-52-57.png


Homework Equations


Δu = ∫ [(a-Ru)+bT+cT^2+dT^3]dT

The Attempt at a Solution



The answer of 6447kJ/kmol is given but I am struggling to get to this answer after integrating the above formula and inserting the given values.

Firstly would the integral of [(a-Ru)+bT+cT^2+dT^3]dT
be:

[(a-Ru)+bT^2/2+cT^3/3+dT^4/4] ?
 
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No. The first term should be (a-Ru)T.
 
mjc123 said:
No. The first term should be (a-Ru)T.

Is this because (a-Ru) is a constant?
eg. ∫1 dx = x
 
Yes
 
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Likes   Reactions: DevonZA
mjc123 said:
Yes

Thank you let me give that a try.
 
upload_2017-5-16_11-12-38.png
 

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