Change of variable in a double integral

rashida564
Messages
220
Reaction score
7
Homework Statement
The image bellow is the question
Relevant Equations
Jacobian
Hi everyone, I tried to solve the last part of the question, I substituted back the expression of x and y into the equation of the ellipse, I got that r=1 or r=-1. But got no idea how to find the boundary for theta, I got a guess that, It should be from zero to pi. But got no reason why to believe this.
 

Attachments

  • integral 1.PNG
    integral 1.PNG
    13.7 KB · Views: 177
Physics news on Phys.org
rashida564 said:
Homework Statement:: The image bellow is the question
Homework Equations:: Jacobian

Hi everyone, I tried to solve the last part of the question, I substituted back the expression of x and y into the equation of the ellipse, I got that r=1 or r=-1. But got no idea how to find the boundary for theta, I got a guess that, It should be from zero to pi. But got no reason why to believe this.
After the transformation, the resulting figure is a circle of radius 1, centered at the origin. If r ranges from 0 to 1, what needs to be the range for ##\theta## to sweep out the whole circle?
 
  • Like
Likes vanhees71 and scottdave
From zero to two pi, thanks man
 
Last edited by a moderator:
rashida564 said:
From zero to two pi, thanks man
Right.

BTW, I edited your post. You quoted me as saying "From zero to two pi." I didn't say this, so it's misleading to quote me.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top