Charge inside a spherical conducting shell

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When a charge is placed inside a spherical conducting shell, the electric field within the conducting material is zero due to the redistribution of charges on the inner surface. However, the electric field in the empty space inside the shell is not zero. If a hole exists in the shell and the charge is moved through it, work is required because the electric field in that region is not canceled out. Conversely, moving the charge through the conducting material itself incurs no work since the electric field there is zero. The discussion emphasizes the distinction between the electric field in different regions of the shell and the implications for work and potential energy.
zeeva
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If a charge is placed inside a spherical conducting shell, is the total electric field inside it zero? I am thinking that if the charge is positive, then the conducting shell will have an equal amount of negative charge on its inner surface, therefore the E field should be zero inside, right?
 
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You mean the electric field in the space filled by the conducting material? In that case you're right, it would be zero. That's pretty general, actually: any space filled with conducting material will have zero electric field, because if the electric field were nonzero, it would push around electrons inside the conductor until they canceled out the external field.

Of course the E field in the empty space inside the shell would not be zero.
 
Does that mean that if the shell had a hole through it and we wanted to move the charge from the inner radius to the outer radius, the work would be zero?
 
It would be better to use energy considerations here. The value of potential energy would be different in the initial and the final configurations.

Work done=Change in Potential Energy
 
zeeva said:
Does that mean that if the shell had a hole through it and we wanted to move the charge from the inner radius to the outer radius, the work would be zero?
Not if you move the charge through the hole. The space of the hole is not filled with conducting material, so there's no reason the electric field inside it would be zero.

Of course, if you move the charge through the metal itself, and not through the hole, then the work done would be zero.
 
It may be shown from the equations of electromagnetism, by James Clerk Maxwell in the 1860’s, that the speed of light in the vacuum of free space is related to electric permittivity (ϵ) and magnetic permeability (μ) by the equation: c=1/√( μ ϵ ) . This value is a constant for the vacuum of free space and is independent of the motion of the observer. It was this fact, in part, that led Albert Einstein to Special Relativity.
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