In summary: But doesn't that change the calculation of v\,=\,i\,R?v\,=\,i\,R\,=\,(-1.429\,A)\,(10\Omega)\,=\,-14.3\,VVS.v\,=\,i\,R\,=\,(-11.43\,A)\,(10\Omega)\,=\,-114.3\,VI'm thoroughly...thoroughly confused. :(hmmmm, let me see. The i = -1.429A is the current through 10ohm. So the voltage is -14.29V through both resistors. The voltage
#36
Number2Pencil
208
1
the problem is you set V6 = V of the V.C.C.S. remember it's both resistors combined
I updated that diagram to hopefully make it more obvious