Engineering Circuit (equivalent resistance)

AI Thread Summary
To find the equivalent resistance in a circuit, it's essential to identify series and parallel connections. The user struggles with visualizing these connections and simplifying the circuit. Marking junctions and potential points can aid in understanding the layout, as potential remains constant across parallel resistors and adds up in series. Clarifying the arrangement of resistors can help distinguish between series and parallel configurations. Understanding these concepts is crucial for solving the problem effectively.
triforce
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Homework Statement


Find the equivalent resistance
Aib5Oqj.jpg

Homework Equations


Req(series) = R1 + R2...
Req(parallel)=(1/R1+1/R2...)^-1

The Attempt at a Solution


I'm having problems understanding how to simplify this circuit.
There should be parallel and series "loops" to simplify but I'm having trouble seeing them.
 
Last edited:
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triforce said:
I'm having problems understanding how to simplify this circuit.
There should be parallel and series "loops" to simplify but I'm having trouble seeing them.
Mark the junctions where potential is a . Consider a random voltage V , which is the potential in between the 2Ω and 3Ω resistors .

Now draw a fresh diagram , now marking a , b and V , and connecting resistors between the three appropriately . This should help in simplifying the circuit , making it easy to see the series and parallel connections .

Hope this helps .
 
Updated the image with the resistors numerated in red.

Do you have to consider potential?
 
Yes , the potential is what I mentioned in my previous post .
 
What i know is that potential stays the same across parallel sections and is summed up in series.

How does that help me if i can't distinguish which one is in parallel or in series?

Would you mind to explain a little further please, I'm kind of new to this.
 
Look at the bottom end of R2...imagine sliding it to the left and around the corner.
 

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