Circuit for determining the internal resistance of a dry cell

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To determine the internal resistance of a dry cell, set up a circuit with a variable resistor in series with an ammeter and a voltmeter. Measure the open circuit voltage to find the EMF, and then apply a load using the variable resistor to create a current flow. Monitor the voltage drop across the resistor while measuring the current to assess the internal resistance. If the voltage drops significantly, such as to half, the resistance can be equated to the internal resistance of the battery. For rechargeable cells, a smaller voltage drop, around 10%, is recommended to avoid excessive current.
jackmannn
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What sort of circuit would I have to set up to figure out the internal resistance of a dry cell? Also, what would i need to be measuring and doing etc, to find this internal resistance?

Thanks, Jack.
 
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A battery is considered to be an EMF in series with a resistor.

You can measure the EMF by measuring the open circuit voltage of the battery. There is no voltage drop across a resistor if there is no current flowing through it.

To put a load on the battery and measure the current and voltage, you could use something like the attached diagram.

A voltmeter monitors the output voltage. A variable resistor R is placed in series with the ammeter.
You can monitor the voltage while the heavy load (R) is placed across the battery. A large rheostat would be suitable for R.

Suppose R makes the output voltage drop to half. Then you could say that R is equal to the internal resistance.
You can calculate the value of R by measuring the voltage across it and the current through it.
The voltage does not have to drop to half. If you were testing a rechargeable cell, a NiMH or NiCd cell, you would not do this because these can deliver very large currents. So, maybe a 10% drop would be OK for these.

You just calculate the value of the internal resistance knowing the current flowing and the voltage drop between no load and the measured load.
 

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