Engineering Circuit Voltage Dynamic Equations

AI Thread Summary
The discussion focuses on deriving dynamic equations for a circuit with two capacitors, one resistor, and a voltage source using Kirchhoff's Current Law. The user presents their equations but expresses uncertainty about their validity, especially when the capacitances are equal. A key point raised is that if the terminals at V1 are open-circuited, no current flows, which affects potential drops. However, the conversation also highlights that a varying voltage source can still influence potential changes despite the lack of current flow. The user seeks clarification on their approach and where they might be going wrong in their analysis.
wilsondd
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Homework Statement



As part of a larger problem, I'm trying to understand the dynamic equations of the attached circuit with two capacitors and one resistor and a voltage source. When I use Kirchoff's Current Law at nodes V0 and V1, I get the following equations.

Homework Equations



See Attachment for circuit diagram


The Attempt at a Solution



When I use Kirchoff's Current Law at nodes V0 and V1, I get the following equations.

0 = (dVs/dt-dV1/dt)*C1 - (V1-V2)/R - (dV1/dt-dV2/dt)*C2
0 = (dV1/dt-dV2/dt)*C2 + (V1-V2)/R

I have a feeling that this approach is wrong though, since I can't solve the equation when C1 = C2. I would be very appreciative if someone could tell me where I'm going wrong.
 

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wilsondd said:

Homework Statement



As part of a larger problem, I'm trying to understand the dynamic equations of the attached circuit with two capacitors and one resistor and a voltage source. When I use Kirchoff's Current Law at nodes V0 and V1, I get the following equations.

Homework Equations



See Attachment for circuit diagram


The Attempt at a Solution



When I use Kirchoff's Current Law at nodes V0 and V1, I get the following equations.

0 = (dVs/dt-dV1/dt)*C1 - (V1-V2)/R - (dV1/dt-dV2/dt)*C2
0 = (dV1/dt-dV2/dt)*C2 + (V1-V2)/R

I have a feeling that this approach is wrong though, since I can't solve the equation when C1 = C2. I would be very appreciative if someone could tell me where I'm going wrong.

If the terminals at V1 are open circuited as shown then no current can flow, so no potential drops will occur...
 
gneill said:
If the terminals at V1 are open circuited as shown then no current can flow, so no potential drops will occur...



Yes, but what if the voltage source is not constant?
 
wilsondd said:
Yes, but what if the voltage source is not constant?

No current can flow. But that doesn't mean the potential cannot change. Anything connected to the top lead of Vs will vary identically in potential w.r.t. to the bottom lead of Vs.
 

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