Circuit with a capacitor problem

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    Capacitor Circuit
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In a series circuit with a capacitor, current can flow due to the capacitor's ability to store and release charge, despite the insulating material between its plates. In DC circuits, the flow of charge is limited by the capacitor's stored charge, while in AC circuits, charge can alternate between the source and the capacitor. Kirchoff's closed loop law can still apply, as the current in the circuit is influenced by the capacitor's charge, even though no charge flows through the capacitor itself. When the capacitor is fully charged, the current effectively becomes zero, as the potential difference across the capacitor matches that of the circuit. Leakage is a minor concern and typically does not significantly affect circuit operation.
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I've just been reading about capacitors and I have some (stupid?) questions... First, how can there be a current in a (series) circuit with a capacitor when there is an insulating material or vacuum between the plates (or whatever makes up the capacitor)?? i don't get it.. Second (pretty much the same as the first), how can you apply Kirchoff's closed loop law to a circuit in which there is a capacitor - it isn't closed when there can be no current through the insulator or vacuum in the capacitor??

I know I posted this twice, but just encountered the College Level Help forum..
 
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First off:

How can there be a current in a circuit that is in series with a capacitor. For DC circuits, the amount of charge that can flow in a circuit like that is effectively limited by the amount of charge that can be stored in the capacitor. (This is effectively the reverse of discharging the capacitor)
In an AC circuit things are a bit more complicated. The capacitor can store charge, so that when the source inverts, charge will flow from the source to the capacitor, or from the capacitor to the source.

I'm not familiar with Kirchoff's closed loop formula, but hopefully the comment above was helpfull.
 
thanks for the answer.. no charge can flow through a capacitor, but there's still a current in the circuit determined by the charge on the capacitor?? i.e. when the capacitor is fully charged I = 0??
 
Technically it's when the potential difference between the capacitor plates is equal to the potential difference on the capacitor leads. ('Fully charged' might require a higher potiential difference that the circuit supplies.)

There is also leakage, butt you shoudn't have to worry about that.
 
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