Circuits: Power, Voltage, Resistance

AI Thread Summary
The discussion focuses on calculating the resistance of a lamp operating at 12V and 24W, determining it to be 6 Ohms. To vary the voltage across the lamp from 0V to 12V, a potentiometer is suggested as the variable resistor. Participants discuss the configuration of the circuit, noting that the potentiometer creates a voltage divider with the lamp's resistance. The challenge lies in calculating the appropriate resistance value for the potentiometer to achieve the desired voltage across the lamp. The conversation emphasizes the need for a clear understanding of the circuit components and their interactions.
barnaby
Messages
17
Reaction score
0

Homework Statement



The circuit shown is used to produce a current-voltage graph for a 12V, 24W lamp:

http://img338.imageshack.us/img338/9139/circuitlu6.jpg
http://img338.imageshack.us/img338/9139/circuitlu6.jpg
a) Calculate the resistance of the lamp in normal operation.
b) Calculate the value for R which wold enable the voltage across the lamp to be varied between 0V and 12V.

Homework Equations



P = IV
V = IR

The Attempt at a Solution



a) P=IV
24 = 12I
I = 2A

V = IR
12 = 2R
R = 6 Ohms

b) Absolutely no idea how to go about doing this... it seems that the voltage across the resistor R ought to be 8V, but I don't know, since we haven't been told what the component with the arrow pointing into the 24 ohm resistor is... Thanks for your help.
 
Last edited by a moderator:
Physics news on Phys.org
barnaby said:

Homework Statement




b) Absolutely no idea how to go about doing this... it seems that the voltage across the resistor R ought to be 8V, but I don't know, since we haven't been told what the component with the arrow pointing into the 24 ohm resistor is...

This is a "potentiometer" A resistor with a sliding contact, forming a variable voltage divider.
you have to determine such that you get 12 V across the lamp if the contact is at the top and 0 V if the contact is at the bottom.
 
So if the contact is at the top, you get what is in effect two resistors in parallel - one at 24 ohms and the other at 6 ohms? I tried solving it like that... and got nowhere - calculated that the total resistance of the two strands of the circuit was 4.8 ohms... don't know if that's helpful at all, though.
 
Last edited:
barnaby said:
So if the contact is at the top, you get what is in effect two resistors in parallel - one at 24 ohms and the other at 6 ohms? I tried solving it like that... and got nowhere - calculated that the total resistance of the two strands of the circuit was 4.8 ohms... don't know if that's helpful at all, though.

That's certainly helpful. Now you have to find the R that makes the voltage divider formed by R and the 4.8 Ohm resistance produce 12 V
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top