Circular Motion of a Mass with Tension in a Rope

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Homework Help Overview

The problem involves analyzing the circular motion of a mass (a 25.0 kg ball) being swung in a near-horizontal arc with a tension of 100 N in the rope. The objective is to determine the rotational speed in rpm.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between tension, weight, and centripetal force, with some questioning the implications of the tension being less than the weight of the ball.

Discussion Status

Some participants have offered guidance on drawing free body diagrams and have attempted to derive velocity from the tension. There are differing interpretations regarding the implications of the tension and the motion's horizontal nature.

Contextual Notes

There is a noted confusion regarding the assumptions of the motion being near-horizontal, particularly in relation to the forces acting on the ball and the resulting acceleration.

d.tran103
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Hey can someone help me with this question? Thanks

Homework Statement


Goferd is getting buff by swinging a 25.0 kg ball in a near - horizontal arc. If the length of the rope that is attached to the ball is 2.00 m, and Goferd maintains a constant tension of 100. N in that rope, how many rpm does this ball rotate with?

A 9.55 rpm

B 13.5 rpm

C 4.63 rpm

D 17.7 rpm


Homework Equations


EFr = Fc = fsmax = UN = MsMg = mac = mv^2/r


The Attempt at a Solution


I tried to work with mv^2/r and mac but need a mass or velocity to find the RPM. I keep getting stuck with two unknowns.
 
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Draw a free body diagram for the ball.

The rope will not be horizontal.
 
I am confused. Tension will balance the weight of the body and also provide centripetal force. But tension is even less than mg of the ball! This means that the ball is accelerating downwards. Hence this is not a near horizontal motion.
 
Assuming a rigid and light rope

since it's near horizontal m*v^2/r=100 --> v≈2.82m/s ----> B) 13.5rpm

(The ball has a vertical acceleration downwards of g-4sin(alpha). Since it's near-horizontal, alpha is approx 0, therefore sin(alpha)≈0 --> downward acceleration ≈ g)
 

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