Clarification on calculating Electrical Force and charge

In summary: He gave you the equations you need. Use those equations to set up a system of equations in two unknowns.In summary, the problem involves two small metal-coated styrofoam spheres with a mass of 2.80e-6 kg each attached to nylon threads 45.0 cm long and hung from a common point. The spheres are charged equally negative and make an angle of 16° with the vertical. The question asks to calculate the charge on each sphere using the equation Fe/Fw = 0.12/0.43. The relevant equations are Fe = kq1q2/d2 and F1/F2 = s2/s1. To solve the problem, a free body diagram for each sphere can
  • #1
yudi
3
0
Please see the following question and the answer. I don't understand how Fe/Fw = 0.12/0.43

Question?
Two small metal-coated styrofoam spheres each of mass 2.80e-6 kg are
attached to nylon threads 45.0 cm long and hung from a common point. The
spheres are then charged equally negative and the angle each supporting thread
makes with the vertical is 16°. Calculate the charge on each sphere.

Answer:

let Fe = electrical force
Fw = Weight force = 2.8e-6 X 9.8 = 2.744e-5 N
if θ = 16°, then hypotenuse = 0.45m, Opposite = 0.12 m, and adjacent = 0.43m

If the system is blanced:

Fe/Fw = 0.12/0.43

Can someone please explain the above equation?

Thank You.
Yudi
 
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  • #2
yudi said:
Please see the following question and the answer. I don't understand how Fe/Fw = 0.12/0.43

Question?
Two small metal-coated styrofoam spheres each of mass 2.80e-6 kg are
attached to nylon threads 45.0 cm long and hung from a common point. The
spheres are then charged equally negative and the angle each supporting thread
makes with the vertical is 16°. Calculate the charge on each sphere.

Answer:

let Fe = electrical force
Fw = Weight force = 2.8e-6 X 9.8 = 2.744e-5 N
if θ = 16°, then hypotenuse = 0.45m, Opposite = 0.12 m, and adjacent = 0.43m

If the system is blanced:

Fe/Fw = 0.12/0.43

Can someone please explain the above equation?

Thank You.
Yudi

Welcome to the PF.

Is there a diagram included with this problem? It would be easier to explain it if you showed the diagram.

Also, what are the relevant equations when solving problems that involve charges and forces? There is an equation that relates the force to the two charges and the distance between them. Can you list that equation please?
 
  • #3
berkeman said:
Is there a diagram included with this problem? It would be easier to explain it if you showed the diagram.

No. There is no diagram given with the question. I used the info in the question to draw the triangle. With 32° at the apex and as the included angle and 0.45 m as the sides.

Also, what are the relevant equations when solving problems that involve charges and forces? There is an equation that relates the force to the two charges and the distance between them. Can you list that equation please?

Fe = kq1q2/d2

To use the above equation, I need the Electrical force. This is where I am stuck.

I looked at the answer and it has the following:
In a balanced system:

F1/F2 = s2/s1

How is Fe/Fw = 0.12/0.43

If the forces are in a straight line, the above equation makes sense but in this case, they are at an angle.
 
Last edited:
  • #4
Draw a free body diagram for each sphere.

The gravitational force is at a right angle to the electric force. Each sphere is in equilibrium, so there must be a third force acting on each sphere.
 
  • #5
No extra information other than what's in the question is given.
Can someone please explain the logic in solving this problem.
I don't need the answer, just pointers on how to solve this question.
 
  • #6
yudi said:
No extra information other than what's in the question is given.
Can someone please explain the logic in solving this problem.
I don't need the answer, just pointers on how to solve this question.

Did you read SammyS' post?
 

Related to Clarification on calculating Electrical Force and charge

1. What is electrical force?

Electrical force is a fundamental force of nature that is responsible for the attraction or repulsion between charged particles. It is also known as the Coulomb force after the physicist Charles-Augustin de Coulomb who first described it.

2. How is electrical force calculated?

The magnitude of electrical force between two charged particles is calculated using Coulomb's law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. The equation is F = k(q1q2)/r2, where F is the force, k is the Coulomb constant, q1 and q2 are the charges of the particles, and r is the distance between them.

3. How is electrical force affected by the charges and distance between particles?

The electrical force between two charged particles is directly proportional to the product of their charges. This means that the larger the charges, the stronger the force. The force is also inversely proportional to the square of the distance between the particles. This means that the farther apart the particles are, the weaker the force between them.

4. How is electrical charge measured?

Electrical charge is measured in a unit called the Coulomb (C). One Coulomb is equal to the amount of charge that passes through a conductor in one second when there is a current of one ampere (A). It can also be measured in smaller units, such as micro-Coulombs (μC) or nano-Coulombs (nC).

5. What is the difference between electrical force and gravitational force?

Electrical force and gravitational force are both fundamental forces of nature, but they have some key differences. Electrical force is caused by the interaction between charged particles, while gravitational force is caused by the attraction between objects with mass. Additionally, electrical force can be either attractive or repulsive, whereas gravitational force is always attractive. Finally, electrical force is much stronger than gravitational force, but it only acts over short distances compared to the infinite range of gravitational force.

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