- #1
yudi
- 3
- 0
Please see the following question and the answer. I don't understand how Fe/Fw = 0.12/0.43
Question?
Two small metal-coated styrofoam spheres each of mass 2.80e-6 kg are
attached to nylon threads 45.0 cm long and hung from a common point. The
spheres are then charged equally negative and the angle each supporting thread
makes with the vertical is 16°. Calculate the charge on each sphere.
Answer:
let Fe = electrical force
Fw = Weight force = 2.8e-6 X 9.8 = 2.744e-5 N
if θ = 16°, then hypotenuse = 0.45m, Opposite = 0.12 m, and adjacent = 0.43m
If the system is blanced:
Fe/Fw = 0.12/0.43
Can someone please explain the above equation?
Thank You.
Yudi
Question?
Two small metal-coated styrofoam spheres each of mass 2.80e-6 kg are
attached to nylon threads 45.0 cm long and hung from a common point. The
spheres are then charged equally negative and the angle each supporting thread
makes with the vertical is 16°. Calculate the charge on each sphere.
Answer:
let Fe = electrical force
Fw = Weight force = 2.8e-6 X 9.8 = 2.744e-5 N
if θ = 16°, then hypotenuse = 0.45m, Opposite = 0.12 m, and adjacent = 0.43m
If the system is blanced:
Fe/Fw = 0.12/0.43
Can someone please explain the above equation?
Thank You.
Yudi