Classical mechanics, angular momentum and velocity not parallel, why?

AI Thread Summary
In the discussion on classical mechanics, the problem involves a particle revolving in a circle and examines why its angular momentum (L) is not parallel to its angular velocity (w). It is established that L, calculated using the cross product of the position vector (r) and linear momentum (P), has components in the x and y axes, indicating it is not parallel to w. The moment of inertia also contributes to this non-parallel relationship due to its perpendicular components. For the second part, the combined angular momentum of two particles at opposite ends of a diameter is discussed, emphasizing that it is the vector sum of their individual angular momenta. Visual aids, such as diagrams, are recommended to clarify the relationships between the vectors involved.
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Homework Statement


A single particle of mass m is revolving at steady speed in a circle of radius a about the z axis at a height h above the origin. In this situation the particle has angular velocity w = wz

1 Show that the angular momentum L is not parallel to w

2 If a second particle revolves in the same circle at the opposite end of a diameter, show that the combined angular momentumof the two particles rotating rigiidly is parallel to w.

Homework Equations




The Attempt at a Solution


For the first question, i have found a webpage that talks about this situation and describes the problem of w and L not being parallel. But I am finding it hard to extract what information to show that this is true. Here is the link: http://sites.isel.ipl.pt/fisica/pedagogia/ajp75(2007)53.pdf

I am concentrating on the first question first so any help would be greatly appreciated.
 
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To answer part (1), consider this:

In rotational motion, angular momentum \stackrel{\rightarrow}{L} = \stackrel{\rightarrow}{r} \times\stackrel{\rightarrow}{P}, where P is linear momentum.
 
simon1987 said:
To answer part (1), consider this:

In rotational motion, angular momentum \stackrel{\rightarrow}{L} = \stackrel{\rightarrow}{r} \times\stackrel{\rightarrow}{P}, where P is linear momentum.

Does this show that the components of L are in the x and y axes as well as z. Therefore it isn't parallel because of this?
 
karnten07 said:
Does this show that the components of L are in the x and y axes as well as z. Therefore it isn't parallel because of this?

I think i have the answer to the first part by showing that the moment of inertia in this case has components that are perpendicular to the z axis therefore L and w arent parallel. Any help on the second part would be much appreciated.
 
karnten07 said:
I think i have the answer to the first part by showing that the moment of inertia in this case has components that are perpendicular to the z axis therefore L and w arent parallel.

Have you drawn a picture? It is incredibly helpful when considering multiple different vectors. Consider: what would the cross product be of z and P if z were parallel to P?

As for part (2), remember that "combined" is just the sum of the two angular momenta, and that each angular momentum is a separate vector. Again, draw a picture.
 
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