Coloumbs Laws and electric fields

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To determine the acceleration of a proton in an electric field of 500 N/C, use the formula F = q * E, where q is the charge of the proton (+e). The force acting on the proton can be calculated, and then acceleration can be found using F = m * a. The acceleration is significantly greater than that due to gravity, which can be calculated for comparison. Understanding the relationship between force, charge, and electric fields is crucial for solving this problem.
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Determine the acceleration of a proton (q = +e, m = 1.67 E -27)
in an electric field of intensity 500 N/C. How many times is this acceleration greater then that due of gravity

I'm not so understanding on todays lessons
teh 2 formulas I can recall are f = q*e
and e = f/q
but i don't see that helping here, can someone help me start off
thanks guys.
 
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HINT: Force = mass x acceleration
 
yup i knew of that
i got mass, I am looking for acceleration
but what's force
f = q * e right
i got e just don't know what q is (what they mean by q = +e)
 
oh roger that
thanks
 
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