- #1
Combining Formulas: Rearrange Equations for F (No Ev)
- Thread starter gareth01422
- Start date
AI Thread Summary
The discussion centers on rearranging two equations to isolate F while eliminating Ev. Participants suggest starting by expressing both equations in terms of Eph and combining them into a single equation. Gareth shares his initial attempt and seeks confirmation on its correctness. Another user confirms the approach and suggests a simplified method for combining the equations. The conversation concludes with Gareth expressing gratitude for the assistance received.
- #2
Firelion
- 16
- 0
Hi,
I´ll help you with the first step:
Both formulas express Eph.
So you have to replace Eph in both of them and write the remaining parts as one equation.
Then the rest should be easy.
Greetings,
Firelion
I´ll help you with the first step:
Both formulas express Eph.
So you have to replace Eph in both of them and write the remaining parts as one equation.
Then the rest should be easy.
Greetings,
Firelion
Last edited:
- #3
- #4
Marta.92
- 1
- 0
Maybe what I'm saying is stupid, but can't you simply put them together?
By doing so, you would have:
hc*t/b= h*f
then you can transform it into
f= hc*t / (b*h)
EDIT: pardon me...I haven't seen that someone had already answered...
By doing so, you would have:
hc*t/b= h*f
then you can transform it into
f= hc*t / (b*h)
EDIT: pardon me...I haven't seen that someone had already answered...
- #5
Firelion
- 16
- 0
Seems perfectly correct to me.
- #6
gareth01422
- 25
- 1
Firelion said:
Brilliant
Thanks for the help guys.
Gareth
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19.
For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Let's declare that for the cylinder,
mass = M = 10 kg
Radius = R = 4 m
For the wall and the floor,
Friction coeff = ##\mu## = 0.5
For the hanging mass,
mass = m = 11 kg
First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on.
Force on the hanging mass
$$mg - T = ma$$
Force(Cylinder) on y
$$N_f + f_w - Mg = 0$$
Force(Cylinder) on x
$$T + f_f - N_w = Ma$$
There's also...
This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is
The second part of the problem is exactly why you get this affect.
And one more spoiler:
Similar threads
Hot Threads
-
Collision of a bullet on a rod-string system: query
- Started by palaphys
- Replies: 71
- Introductory Physics Homework Help
Recent Insights
-
Insights Quantum Entanglement is a Kinematic Fact, not a Dynamical Effect
- Started by Greg Bernhardt
- Replies: 7
- Quantum Physics
-
Insights What Exactly is Dirac’s Delta Function? - Insight
- Started by Greg Bernhardt
- Replies: 0
- General Math
-
Insights Relativator (Circular Slide-Rule): Simulated with Desmos - Insight
- Started by Greg Bernhardt
- Replies: 1
- Special and General Relativity
-
Insights Fixing Things Which Can Go Wrong With Complex Numbers
- Started by PAllen
- Replies: 7
- General Math
-
Insights Fermat's Last Theorem
- Started by fresh_42
- Replies: 91
- General Math
-
Insights Why Vector Spaces Explain The World: A Historical Perspective
- Started by fresh_42
- Replies: 0
- General Math