Comparing Flux of a Closed Cylinder

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Homework Help Overview

The discussion revolves around the electric flux through a closed cylinder with a negatively charged particle placed outside one end. Participants are comparing the flux through the left end of the cylinder with that through the right end, considering the contributions from the curved sides as well.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the direction of the electric field and its effect on the flux through the ends of the cylinder. Questions are raised about the contribution of the curved sides to the total flux and the laws governing electric flux from point charges.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem. Some have suggested methods for calculating the flux through differential areas, while others are questioning the relevance of the curved sides and the laws that apply to the scenario.

Contextual Notes

There is an indication that the problem may involve integrating over specific geometrical parameters, but details about the assumptions or constraints of the homework are not fully established.

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Homework Statement


A closed cylinder consists of two circular end caps and a curved side. A negatively charged particle is placed outside the left end of the cylinder, on its axis. Compare the flux through the left end of the cylinder with that through the right.


2. The attempt at a solution

I know the field points out of the cylinder on the left end, and into the cylinder on the right, so the flux through the left end is positive while that through the right end is negative. But what above the sides of the curves?
 
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Does the question ask you about the curved sides?
What law tells you how the electric flux from a point charge, through a fixed area, changes with distance?
 
Let
charge located at x = 0
near end locared at x = d
length of cylinder = L
R = radius of ends

1. Compute the flux through a differential annulus for the near end. Integrate from r = 0 to r = R parametrically using θ = arc tan r/d.
2. Do the same for the far end. Realize θ will range from 0 to a smaller number than for the near end.
3. Compare.
 
Thanks !
 

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