I was wondering if it's something to do with normal distribution or central limit theorem but honestly, I have no idea at all on how to solve this question
#4
candyduz
3
0
I tried to approximate normal to binomial and out of groups of 20 flips, for the first set, I got 10, 6, 9, 8, 8, 11, 11, 10, 9, 11 "0"s and for the second set, I got 12, 9, 9, 9, 10, 12, 10, 12, 11, 11 "0"s.
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Hello,
This is the attachment, the steps to solution are pretty clear. I guess there is a mistake on the highlighted part that prompts this thread.
Ought to be ##3^{n+1} (n+2)-6## and not ##3^n(n+2)-6##. Unless i missed something, on another note, i find the first method (induction) better than second one (method of differences).