Complex Impedance: Solve Homework Problem

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The discussion focuses on calculating the complex impedance of a circuit containing a capacitor and a resistor. Given the voltage across the capacitor (3.2V), the voltage across the resistor (4.65V), and a current of 0.0989A, the phase difference between the voltages is 90 degrees. The formula for complex impedance is presented as Z = R + jX, where R is the resistance and X is the reactance. The user expresses uncertainty about the calculations but gains clarity after reviewing algebra concepts. The thread concludes with the user feeling more confident in solving the problem.
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Homework Statement


In a circuit consisting of a capacitor (Voltage across is 3.2V) and a 47\Omegaresistor (Voltage across is 4.65V), with a current of 0.0989A and a phase difference between the two voltages being 90', what is the complex impedance for the circuit?

Unsure of how to work this out, the stated values are ones I have worked out and may not necessarily be useful to this problem.

Homework Equations


The Attempt at a Solution


Wouldn't know where to start
 
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Z = R +jX=R-j\frac{|V_c|}{|I_c|}
 
Thanks a ton, I think I get it now, had to brush up on a bit of my old algebra notes.
 

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