Complex Number RLC Series Parallel Voltage and Current Supply

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
6 replies · 2K views
badsanta010
Messages
7
Reaction score
0
Hi Everyone.

I have been looking at this questions for a while now and have just hit a brick wall.

I have found the source impedances using the the following

Z of Current source = 1KΩ - jXC

=1000 - j4000Ω = 4123<-75.96°


Z of Voltage source = 4KΩ + jXL

= 4000 + j1000Ω = 4123<14.04°

Correct ?

But from here I am not sure how to approach determining the current I2.

Any kind of guidance would be greatly appreciated.

Thanks
 

Attachments

  • Problem.jpg
    Problem.jpg
    46.3 KB · Views: 538
Physics news on Phys.org
how did you got your value for Xc ?
 
Plus ! you can use KVL in the loop having voltage source !
 
lazyaditya said:
how did you got your value for Xc ?

Using the following formula:

1/jwC

=1/j(25K rads/sec)(10nF)

Thanks
 
shouldn't the angular frequency should be converted into hz ?
 
I could'nt be sure but I assumse that when the formula states Omega it uses its standard form.
 
i think we need to convert it !