Compressed nitrogen v flow rate question

AI Thread Summary
To determine how many cylinders of oxygen-free nitrogen are needed for a machine consuming 16 liters per minute, the total volume of gas in the cylinder (9.78 cubic meters) must be converted to liters, resulting in approximately 9,780 liters. At a flow rate of 16 liters per minute, each cylinder will last about 1 hour and 20 minutes. The pressure of the cylinder (200 bar) and the machine's operating pressure (6 bar) are crucial for accurate calculations, as they affect the usable gas volume. The ideal gas law can be applied to estimate usage, and similar calculations can be performed for other gases like argon. Accurate vendor specifications for cylinder volume are recommended for precise planning.
yoyo28
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Currently i have a system using bulk argon and i am changing to nitrogen. To trial this i am going to use cylinders
of OFN(oxygen free nitrogen). how do i caculate how many cylinders i need based on a flow rate of 16 liters/min.

Thanks
 
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Its a 44-w (9.78 Cubic Mtrs) @200bar going into a machine that consumes 16 liters of gas per minute. how many of these cylinders would i need and how do you calculate usage?

Thanks
 
yoyo28 said:
consumes 16 liters of gas per minute
You know how fast you're using it.
yoyo28 said:
(9.78 Cubic Mtrs)
You know how much is in a cylinder.
You can calculate how long a cylinder will last at that rate. Decide how long you'll run on nitrogen and calculate the number of cylinders you need.
 
Does it matter what pressure the cylinder is at(200bar) v machine (6bar).
 
The way I read the link for the "44-W," the 9.78 is the content of the cylinder at STP. Now you've given me a lower service pressure of 6 bar (gauge or absolute?) which changes things. For your purposes the cylinder will be empty at 6 bar, gauge will be different from absolute. Any other details to add before we start a rough calculation?
 
this is gauge pressure. what formula are you using?
 
For seven atm., the ideal gas equation of state should be good enough. 9.78 over 7 is 1.4 m3 for your use, - 44 liter left in the cylinder when "empty" is 1.35, over 16 liter/min is an hour and 20 minutes per bottle. You'll want to check with the vendor about the 9.78 m3, but that looks about right.
 
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Thanks, would this be the same calculation for other gas(argon). ie machine with flowrate of 0.5l(argon/nitrogen) per minute. So 1.35/0.5 = 2700 min.
why are you deviding by 7?
 
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You're running at an absolute pressure of seven atmospheres.
 
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