 #1
 35
 0
Hello, Im currently working through Faraday's Law and im confused when my two textbooks dont explain how they set the polarity of [tex]V_{emf}[/tex], particularly when they say "the sign convention for [tex]V_{emf}[/tex] is arbitrary in that it depends on the assumed direction for dS". How is the polarity related to dS?
The formula im using is [tex]v_{emf} =  \int_c \vec{B}\cdot d\vec{S} = \oint_c \vec{E}\cdot d\vec{L}[/tex]
Here's a diagram that you can try explaining it from.
Thanks!
The formula im using is [tex]v_{emf} =  \int_c \vec{B}\cdot d\vec{S} = \oint_c \vec{E}\cdot d\vec{L}[/tex]
Here's a diagram that you can try explaining it from.
Thanks!
Attachments

10.2 KB Views: 793
Last edited: