- #1

nyxynyx

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Hello, I am currently working through Faraday's Law and I am confused when my two textbooks don't explain how they set the polarity of [tex]V_{emf}[/tex], particularly when they say "the sign convention for [tex]V_{emf}[/tex] is arbitrary in that it depends on the assumed direction for dS". How is the polarity related to dS?

The formula I am using is [tex]v_{emf} = - \int_c \vec{B}\cdot d\vec{S} = \oint_c \vec{E}\cdot d\vec{L}[/tex]

Here's a diagram that you can try explaining it from.

Thanks!

The formula I am using is [tex]v_{emf} = - \int_c \vec{B}\cdot d\vec{S} = \oint_c \vec{E}\cdot d\vec{L}[/tex]

Here's a diagram that you can try explaining it from.

Thanks!

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