Confused about the absolute value of a complex number

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SUMMARY

The absolute value of a complex number, represented as |z|, is defined as |z| = sqrt(x^2 + y^2), where z = x + iy. This definition aligns with the Euclidean distance in R^2, contrasting with the real number absolute value, |a| = sqrt(a^2), which applies only in R^1. The discussion clarifies that the modulus of a complex number cannot be generalized from real numbers due to the nature of complex fields. Additionally, the concept extends to higher dimensions, such as quaternions and polynomials, where the absolute value or norm is calculated similarly using the sum of squares of their components.

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  • Understanding of complex numbers and their representation (x + iy)
  • Familiarity with Euclidean distance in R^2
  • Basic knowledge of quaternions and their properties
  • Concept of norms in mathematical spaces
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  • Study the properties of complex numbers in detail, focusing on modulus and argument.
  • Learn about quaternions and their applications in 3D graphics and physics.
  • Explore the concept of norms in various mathematical spaces, including polynomial spaces.
  • Investigate the implications of complex analysis in advanced mathematics and engineering.
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torquerotates
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Let z be the complex number: x+iy. Then |z|^2=x^2+y^2 according to my book. But according to the general definition of absolute value, |a|=(a^2)^.5. So letting z=a=x+iy. |z|^2=z^2=x^2+2ixy-y^2

This is not equal to x^2+y^2. I'm confused.
 
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|x| = \sqrt{x^2} is only true for x \in \mathbb{R}. You can think of Complex numbers as a 2-tuple of Reals.

In general

if

x = (x_1, x_2, ..., x_n)

then

|x| = \left(x_1^2 + x_2^2 + ... + x_n^2\right)^{\frac{1}{2}}

This might be of interest to you: http://en.wikipedia.org/wiki/Norm_(mathematics)#Euclidean_norm
 
Last edited:
In complex analysis |z| is called the the modulus. Since the complex field is not well ordered (meaning we can't say stuff like 3<5) then we cannot generalize the real value absolute value into the complex field. Instead we define |z| = Sqrt[x^2 + y^2]. This is consistent with the real valued absolute value when y = 0.
 
PowerIso said:
In complex analysis |z| is called the the modulus.
"absolue value" and "norm" are frequently used too.


cannot generalize the real value absolute value into the complex field.
But, but, you just did! See:

Instead we define |z| = Sqrt[x^2 + y^2]. This is consistent with the real valued absolute value when y = 0.
 
torquerotates said:
Let z be the complex number: x+iy. Then |z|^2=x^2+y^2 according to my book. But according to the general definition of absolute value, |a|=(a^2)^.5. So letting z=a=x+iy. |z|^2=z^2=x^2+2ixy-y^2

This is not equal to x^2+y^2. I'm confused.

The idea of the absolute value is related to the (Euclidean) distance of the point. That means, if we treat each component as a dimension in boring-old R^n, the absolute value is the distance from the point in question from the origin. This is the definition you should start with.

For reals, we don't have any complex part, so we're really working on R^1. Take any point x. The absolute value of x, |x|, is the distance between x and 0. In other words, sqrt(x^2).

For the complex numbers, we have another component, the imaginary part, as well as the real part. Take any point c. The absolute value of c, |c|, is the distance between c and 0. We're working in R^2 now, so we use the pythagorean theorem or the distance formula or whatever you want to call it. |c| = |a + bi| = sqrt(a^2 + b^2).

Now, there are other things for which this definition continues to work, too. Quaternions are a system of numbers where we have THREE complex values, i, j, and k, which are all distinct and unique. They satisfy a few interesting properties: i*i = j*j = k*k = i*j*k = -1. Like matrices, quaternions don't commutative on multiplication, and for any two quaternions p and q, q*p need not equal p*q. But the full details aren't important.

Take any quaternion q = x + a*i + b*j + c*k. We have two use four components now, as opposed to 2 for the complex numbers and only 1 for the reals. So we're working with distance in R^4. The formula for distance in R^4 follows suit with R^2: it is the root of the sum of the squares. So |q| = |x + a*i + b*j + c*k| = sqrt(x^2 + a^2 + b^2 + c^2).

It's like magic!

We can even use weirder spaces, such as the linear space of polynomials. The polynomials are functions defined like f(x) = a_n x^n + ... + a_1 x_1 + a_0. We can add two polynomials f and g together to create a new polynomial f+g defined by (f+g)(x) = f(x) + g(x). We can also multiply a polynomial f with a scalar a to get a new polynomial a*f defined by (a*f)(x) = a * f(x).

We can define the "absolute value" of a polynomial (we might call it a "norm" instead) in the exact same way! Any polynomial of order n (where the highest exponent of x is x^n) is defined uniquely by n+1 real numbers. So |f| = |x -> a_n x^n + ... + a_1 x + a_0| = sqrt(a_n^2 + ... + a_1^2 + a_0^2).

So when you think of |x| for a real x as sqrt(x^2), remember that this is only because real numbers only have one real component (themselves). For higher-dimensional objects, you'll have the more general form |x| = sqrt(a_0^2 + a_1^2 + ... + a_n^2).
 
Relativistic Momentum, Mass, and Energy Momentum and mass (...), the classic equations for conserving momentum and energy are not adequate for the analysis of high-speed collisions. (...) The momentum of a particle moving with velocity ##v## is given by $$p=\cfrac{mv}{\sqrt{1-(v^2/c^2)}}\qquad{R-10}$$ ENERGY In relativistic mechanics, as in classic mechanics, the net force on a particle is equal to the time rate of change of the momentum of the particle. Considering one-dimensional...

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