- #1
- 228
- 3
I can't understand how the D'Alembertian x 4-vector Vector potential = mu x 4-vector J
Have
[tex]\nambla^2\A-1\c^2\ frac{ \partial^{2}A}{\partial {t}^{2} } } = \-mu\J[/tex]
Have
[tex]\nambla^2\A-1\c^2\ frac{ \partial^{2}A}{\partial {t}^{2} } } = \-mu\J[/tex]
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