- #1

- 228

- 3

I can't understand how the D'Alembertian x 4-vector Vector potential = mu x 4-vector J

Have

[tex]\nambla^2\A-1\c^2\ frac{ \partial^{2}A}{\partial {t}^{2} } } = \-mu\J[/tex]

Have

[tex]\nambla^2\A-1\c^2\ frac{ \partial^{2}A}{\partial {t}^{2} } } = \-mu\J[/tex]

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