Conservation of Angular Momentum of particle

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Homework Help Overview

The problem involves a completely inelastic collision between two particles, one with a mass of 2.80 kg moving vertically and the other with a mass of 4.00 kg moving horizontally. The goal is to determine the angular momentum of the combined particles with respect to the origin after the collision.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants express confusion regarding the use of different coordinate systems (ij and xy) and how they relate to the calculation of angular momentum. There are attempts to clarify the relationship between the two systems and the definition of angular momentum.

Discussion Status

Some participants have offered insights into the relationship between the two coordinate systems and how to approach the problem. There is an acknowledgment of the angular momentum vector's orientation and its relationship to the position and velocity vectors. However, the discussion does not reach a consensus on the approach, as confusion remains regarding the calculations.

Contextual Notes

Participants are navigating the complexities of vector calculations in different coordinate systems, which may be impacting their understanding of the problem. The original poster indicates a need for foundational guidance to begin the calculations.

Versaiteis
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Homework Statement



A 2.80 kg particle that is moving horizontally over a floor with velocity (-3.00 m/s) \widehat{j}undergoes a completely inelastic collision with a 4.00 kg particle that is moving horizontally over the floor with velocity (4.55 m/s)\widehat{i}. The collision occurs at xy coordinates (-0.50 m, -0.10 m). After the collision, what is the angular momentum of the stuck-together particles with respect to the origin?

answer = 6.02\widehat{k} kg*m^2/s

Homework Equations



L = m( r x v )

The Attempt at a Solution



I can't seem to understand exactly what I'm supposed to do, what keeps throwing me off is the two different coordinate systems, ij and xy. No matter what combinations of vectors I use, nothing comes close, so I guess what I'm looking for is a place to start.
 
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Versaiteis said:
L = m( r x v )

The Attempt at a Solution



I can't seem to understand exactly what I'm supposed to do, what keeps throwing me off is the two different coordinate systems, ij and xy. No matter what combinations of vectors I use, nothing comes close, so I guess what I'm looking for is a place to start.
Keep in mind that the angular momentum vector is always perpendicular to the plane of \vec{r} \text{ and } \vec{v}.

The i, j, and k axes are all perpendicular to each other, of course. \hat i is the unit vector along the x-axis in the direction of + x. \hat j is the unit vector along the y-axis in the direction of +y. The \hat k direction is perpendicular to both the i and j unit vectors.

AM
 
Oh I see, the two systems are directly related so I can simply say

L = L_{1} + L_{2}

L_{1} = 2.8 * (-0.5 * -3.00)
L_{2} = 4.0 * ( 0 - (-0.1 * 4.55))

Sure enough

L = 6.02\widehat{k} kg*m^2/s

Thank you for your help Andrew
 
Versaiteis said:
Oh I see, the two systems are directly related so I can simply say

L = L_{1} + L_{2}

L_{1} = 2.8 * (-0.5 * -3.00)
L_{2} = 4.0 * ( 0 - (-0.1 * 4.55))

Sure enough

L = 6.02\widehat{k} kg*m^2/s

Thank you for your help Andrew
No problemo.

AM
 

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