Conservation of energy of a marble problem

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SUMMARY

The discussion centers on a physics problem involving the conservation of energy as a marble rolls down a symmetric bowl. The marble starts from rest at a height 'h' on the left side, where it rolls without slipping due to sufficient friction. The right side of the bowl is smooth and coated with oil, resulting in no friction. The key conclusion is that since the marble rolls without slipping, the work done by friction does not result in energy loss, allowing for a straightforward application of conservation of energy principles.

PREREQUISITES
  • Understanding of conservation of energy principles in physics
  • Knowledge of rolling motion and friction concepts
  • Familiarity with the dynamics of rigid bodies
  • Basic problem-solving skills in mechanics
NEXT STEPS
  • Study the principles of conservation of energy in mechanical systems
  • Explore the effects of friction on rolling objects
  • Learn about the dynamics of rigid body motion
  • Investigate the impact of different surface conditions on motion
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of energy conservation in rolling motion scenarios.

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Homework Statement


A uniform marble rolls down a symmetric bowl, starting from rest at the top of the left side. The top of each side is a distance h above the bottom of the bowl. The left half of the bowl is rough enough to cause the marble to roll without slipping, but the right
half has no friction because it is coated with oil. (a) How far up the smooth side will the marble go, measured vertically from the bottom?


Homework Equations



Conservation of energy

The Attempt at a Solution


While applying conservation of energy, why we should not consider the work done by the friction force on the marble? Kindly explain me.
 
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Because the marble rolls without slipping, there is no heat generated at the point of contact so no Joules are lost to friction. For heat to be generated, the two surfaces need to rub against each other.
 
ok, Thanks :)
 

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